Steel Buildings in Europe

Title A.3 Worked Example – Simply supported, secondary composite beam 6 of 10 4 – 76 where: n r = 1 h p = 58 mm b 0 = 82 mm h sc = 100 mm  1 0,717 58 100 58 82 1 0,7 t          k ≤ k tmax = 0,75               1,25 ; 0,29 1 19 25 31000 1,25 19 / 4 Min 0,8 450 0,717 2 2 Rd  P 3 10     Min 81,66 kN ; 73,73 kN 0,717   P Rd = 52,86 kN 3.6.4. Degree of shear connection The degree of shear connection is defined by: c,f c N N   EN 1994-1-1 § 6.2.1.3 (3) where: N c is the design value of the compressive normal force in the concrete flange N c,f is the design value of the compressive normal force in the concrete flange with full shear connection At mid-span the compressive normal force in the concrete flange represents the total connection. A c is the cross-sectional area of concrete, so at mid-span A c = b eff h c h c = h - h p = 120 – 58 = 62 mm  A c = 1875 × 62 = 116250 mm 2         3 10 1,5 25 116250 0,85 0,85 0,85 c ck c c cd c,f  f A A f N 1647 kN The resistance of the shear connectors limits the normal force to: N c = 0,5 n P Rd = 0,5 × 36 × 52,86 = 952 kN  0,578 1647 952 c,f c    N N  The ratio  is less than 1,0 so the connection is partial.