Steel Buildings in Europe

Title 3.4 Worked Example – Fin Plate 11 of 13 5 – 48 k 1 =         min 2,8 1,7; 1,4 1,7; 2,5 0 1 0 1 d p d e =         1,7; 2,5 22 1,7; 1,4 70 22 min 2,8 40 =   min 3,39; 2, 75; 2,5 = 2,5 α b =          ; 1,0 ; 4 1 3 ; 3 min u,p ub 0 2 0 2 f f d p d e =          ; 1,0 430 ; 800 4 1 3 22 ; 60 3 22 min 50 =   min 0,75; 0,66; 1,86; 1,0 = 0,66 F b,hor,u,Rd = 3 10 1,1 2,5 0, 66 430 20 10       = 129 kN F Rd = 10 129  = 1290 kN F Ed = 350 kN ≤ 1290 kN, OK 3.3.1.3. Tension resistance of the fin plate Basic requirement : F Ed ≤ F Rd F Rd =   Rd,n Rd,b ; min F F Tension resistance of net section F Rd,n = Mu u,p net 0,9  f A Ref [8] A net =   0 1 p p t h d n  =   10 360 22 5   = 2500 mm 2 F Rd,n = 3 10 1,1 430 0,9 2500    = 880 kN Block tearing resistance Case 1 F Rd,b = M0 y,p nv Mu nt u,p 3   f A f A  Ref [8] A nt = t p [( n 1 – 1) p 1 – ( n 1 – 1) d 0 ] = 10[(5 – 1)  70 – (5 – 1)22] = 1920 mm 2 1540 22 2 2 10 50 60 3 2 3 2 0 2 p 2 nv                      t e p d A mm 2 F Rd,b = 3 10 3 1, 0 1540 275 1,1 1920 430               = 995 kN Case 2 A nt =       0 1 1 1 p 1 0,5 1 d t e n p n     A nt =       10 40 5 1 70 5 0,5 22       = 2210 mm 2