Steel Buildings in Europe

Part 5: Joint Design 5 – 64 where: M pl,1,Rd,u = Mu u,ac 2 eff ac Σ 0, 25  l t f M pl,2,Rd,u = M pl,1,Rd,u m = 2 2 2 0,8 ac 3 w r t t p      n = e min but n ≤ 1,25 m where e min = e 2 e w = 4 w d d w is the diameter of the washer k 2 = 0,63 for countersunk bolts = 0,9 otherwise A is the tensile stress area of the bolt, A s Σ l eff is the effective length of a plastic hinge Σ l eff = 1A 1 1A ( 1) 2 e n p   e 1A = e 1 but ≤ 2 2 ) 0,5( 0 3 w d r t p    p 1A = p 1 but ≤ 0 3 w 2 r d t p    4.3.1.2 Shear resistance of bolts Basic requirement: F Ed ≤ F Rd F Rd = 2 n b F v,u F v,u = Mu v ub   f A where: α v = 0,6 for 4.6 and 8.8 bolts = 0,5 for 10.9 bolts A is the tensile stress area of the bolt, A s 4.3.1.3 Bearing resistance of bolts on the angle cleats Basic requirement: F Ed ≤ F Rd F Rd = 2 n b F b,hor,u,Rd F b,hor,u,Rd = Mu ac u,ac 1 b   dt f k