Steel Buildings in Europe

Title APPENDIX D Worked Example: Design of portal frame using elastic analysis 7 of 44 4 - 88 The equivalent horizontal forces: H EHF =  V Ed,column = 168 3,56 10 3    = 0,60 kN This force is applied at the top of each column, in combination with the permanent and variable actions. For the ULS analysis, the bases are modeled as pinned. Otherwise the base details and foundation would need to be designed for the resulting moment. The following figure shows the internal forces on the frame subject to the ULS loads including the equivalent horizontal forces.